How to fill in the gaps 1:49:09 AM
I need help with this!
I like this exercise but I cannot seem to find its ideal solution. Could someone suggest in pseudocode, please..?
# finds files with a give prefix in a folder
# locates any gaps in the numbering
# renames all the later files to close the gaps
# Usage: python gaps.py
import sys
import os
import shutil
import re
'''
Pseudocode:
-find source
-list all files in source folder
-filter in files starting with given prefix
-loop over length of filtered files
- 001, 010, 100
'''
if len(sys.argv) == 3:
source = sys.argv[1]
source = os.path.abspath(source)
if os.path.exists(source):
textFiles = []
numbering = []
prefix = sys.argv[2]
reg = re.compile(r"^{}(\d+).txt$".format(prefix))
for file in os.listdir(source):
if reg.match(file):
textFiles.append(file)
match = reg.match(file)
match = match.groups()[0]
match = int(match)
numbering.append(match)
if len(textFiles) > 0:
gap = None
for iterator in range(len(textFiles)):
if iterator not in numbering:
reg = re.compile(r"^{}(0+)\d*.txt$".format(prefix))
m = (reg.match(textFiles[iterator]))
if m:
m = m.groups()[0]
else:
m = ""
for jterator in range(iterator, len(textFiles)):
curFile = textFiles[jterator]
curFile = os.path.join(source, curFile)
new_name = prefix + m + str(jterator) + ".txt"
new_filename = os.path.join(source, new_name)
shutil.move(curFile, new_filename)
else:
print("There are no other files with that prefix")
else:
print("Provide valid source path")
else:
print("Usage: python gaps.py ")
